Trigonometry MCQs

Question 1

If tanθ + cotθ = 5, then tan 2 θ + cot 2 θ is?

Accepted Answer

23

Answer

24

Answer

25

Answer

26

Question 2

If secθ + tanθ = p, (p > 1) then $$\frac{{{	ext{cosec}}\,	heta + 1}}{{{	ext{cosec}}\,	heta - 1}} = ?$$

Accepted Answer

p 2

Answer

2p 2

Answer

$$\frac{{p + 1}}{{p - 1}}$$

Answer

$$\frac{{p - 1}}{{p + 1}}$$

Question 3

$$\sqrt {\frac{{\cot 	heta + \cos 	heta }}{{\cot 	heta - \cos 	heta }}} $$ is equal to-

Accepted Answer

secθ + tanθ

Answer

1 - secθtanθ

Answer

secθ - tanθ

Answer

1 + secθtanθ

Question 4

If tan 2 A - 6tanA + 9 = 0, 0° < A < 90°, What is the value of 6cotA + $$8\sqrt {10} $$ cosA?

Accepted Answer

10

Answer

$$10\sqrt {10} $$

Answer

14

Answer

$$8\sqrt {10} $$

Question 5

If 1 + sin 2 θ - 3sinθcosθ = 0, then the value of cotθ is:

Accepted Answer

2

Answer

$$\frac{1}{3}$$

Answer

$$\frac{1}{2}$$

Answer

0

Question 6

If 7sin 2 θ + 3cos 2 θ = 4, (0° ≤ θ ≤ 90°), then the value of θ is?

Accepted Answer

$$\frac{\pi }{6}$$

Answer

$$\frac{\pi }{2}$$

Answer

$$\frac{\pi }{3}$$

Answer

$$\frac{\pi }{4}$$

Question 7

If secθ + tanθ = 2 + $$\sqrt 5 {	ext{,}}$$ then the value of sinθ + cosθ is?

Accepted Answer

$$\frac{3}{{\sqrt 5 }}$$

Answer

$$\sqrt 5 $$

Answer

$$\frac{7}{{\sqrt 5 }}$$

Answer

$$\frac{1}{{\sqrt 5 }}$$

Question 8

In a triangle ABC, ∠ABC = 75° and ∠ACB = $$\frac{{{\pi ^c}}}{4},$$ the circular measure of ∠BAC is?

Accepted Answer

$$\frac{\pi }{3}$$ radian

Answer

$$\frac{{5\pi }}{{12}}$$ radian

Answer

$$\frac{\pi }{6}$$ radian

Answer

$$\frac{\pi }{2}$$ radian

Question 9

If tanθ - cotθ = 0 find the value of sinθ + cosθ ?

Accepted Answer

$$\sqrt 2 $$

Answer

0

Answer

1

Answer

2