Pointer MCQs

The address operator &, cannot act on

The statement int **a;

What will be the output of the following program?

#include<stdio.h>
void main()
{
      int i = 10;
      void *p = &i
      printf("%d\n", (int)*p);
}

What will be the output of the following program code?

#include<stdio.h>
void main()
{
      int i = 10;
      void *p = &i
      printf("%f", *(float *)p);
}

The operator > and < are meaningful when used with pointers, if

The declaration int (*p) [5]; means

Comment on the following? const int *ptr;

Determine Output:

#include<stdio.h>
void main()
{
      int *ptr, a=10;
      ptr = &a
      *ptr += 1;
      printf("%d, %d", *ptr, a);
}

A function 'p' that accepts a pointer to a character as argument and returns a pointer to an array of integer can be declared as